Track and display subdomains under their root domain
Adds sites.root_domain (indexed string, backfilled for existing rows)
computed via a naive "last two labels" heuristic (App\Support\RootDomain)
— good enough for example.com/somesite.es, but wrong for two-part
public suffixes like .co.uk. Doing that correctly needs the Mozilla
Public Suffix List; flagged as a known simplification rather than
built now.
Deliberately not a hard FK: like Backlink.target_domain, a subdomain
can get indexed before its root domain does (or vice versa), so
Site::subdomains()/rootSite() match on the domain string rather than
requiring the relationship to exist at write time.
Site detail page: a root domain shows a paginated "Subdomains"
section (same guest-preview cap as Pages/Backlinks); a subdomain
shows "Subdomain of {root}" linking back, when the root is itself
indexed.
Verified against real data: 21k.ro correctly lists its two known
subdomains (buzau.21k.ro, timisoara.21k.ro), each of which correctly
links back to 21k.ro. Added SubdomainsTest (root lists subdomains,
subdomain links to root, empty state) — full suite (31 tests) passes.
This commit is contained in:
@@ -21,12 +21,20 @@ class SiteController extends Controller
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$referringDomainsCount = $site->inboundLinks()->distinct()->count('site_id');
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$outboundLinksCount = $site->outboundLinks()->count();
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$subdomains = GuestPreview::paginate(
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$site->subdomains()->withCount('pages')->orderBy('domain'),
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50,
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'subdomains_page'
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);
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return view('sites.show', [
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'site' => $site,
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'pages' => $pages,
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'backlinks' => $backlinks,
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'referringDomainsCount' => $referringDomainsCount,
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'outboundLinksCount' => $outboundLinksCount,
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'subdomains' => $subdomains,
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'rootSite' => $site->rootSite(),
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]);
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}
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}
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